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Let \( A^{-1}=\left[\begin{array}{ccc}1 & -1 & 2 \\ -1 & 2 & 1 \\ 2 & 1 & -1\end{array}\right] \), then -
(A) \( 7|\mathrm{~A}|=\frac{1}{2} \)
(B) \( \mid \operatorname{adj} \mathrm{Al}=\frac{1}{196} \)
(C) \( \operatorname{trace}(\operatorname{adj} A)=-\frac{1}{7} \)
(D) Matrix A is a symmetric matrix
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