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Let A be the sum of the first 20 terms and B be the sum of the first 40 terms of the series \( 1^{2}+2 \cdot 2^{2}+3^{2}+2 \cdot 4^{2}+5^{2}+2 \cdot 6^{2}+ \) If \( \mathrm{B}-2 \mathrm{~A}=100 \lambda \), then \( \lambda \) is equal to:
\( \mathrm{P} \)
(1) 464
(2) 496
(3) 232
(4) 248
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