Let \( g(x)=f(x) \sin x \), where \( f(x) \) is a twice differentia...
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Let \( g(x)=f(x) \sin x \), where \( f(x) \) is a twice differentiable function on \( (-\infty, \infty) \) such that \( f(-\pi)=1 \). The value of
\( \mathrm{P} \) \( g^{\prime \prime}(-\pi) \) equals
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