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Let \( O \) be the origin and let \( P Q R \) be an arbitrary triangle. The point \( S \) is such that
P
\[
\begin{aligned}
\mathrm{OP} \cdot \mathrm{OQ}+\mathrm{OR} \cdot \mathrm{OS} & =\mathrm{OR} \cdot \mathrm{OP}+\mathrm{OQ} \cdot \mathrm{OS} \\
& =\mathrm{OQ} \cdot \mathrm{OR}+\mathrm{OP} \cdot \mathrm{OS}
\end{aligned}
\]
WV
Then the triangle \( P Q R \) has \( S \) as its \( \quad \) (2017 Adv.)
(a) centroid
(b) orthocentre
(c) incentre
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