Let \( \omega \) be a complex cube root of unity with \( \omega \ne...
Channel:
Subscribers:
443,000
Published on ● Video Link: https://www.youtube.com/watch?v=DIOMV1N_pl8
Let \( \omega \) be a complex cube root of unity with \( \omega \neq 1 \). A fair die is thrown three times. If \( r_{1}, r_{2} \) and \( r_{3} \) are the numbers obtained on the die, then the probability that \( \omega^{r_{1}}+\omega^{r_{2}}+\omega^{r_{3}}=0 \) is
\( \mathrm{P} \)
(A) \( \frac{1}{18} \)
(B) \( \frac{1}{9} \)
(C) \( \frac{2}{9} \)
(D) \( \frac{1}{36} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw