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Match the column-I with column-II.
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ Column-I } & \multicolumn{2}{c|}{ Column-II } \\
\hline A. & \( \begin{array}{l}\text { A charge particle is } \\
\text { moving in uniform } \\
\text { electric and magnetic } \\
\text { fields in gravity free } \\
\text { space. }\end{array} \) & p. & \( \begin{array}{l}\text { Velocity of the particle } \\
\text { may be constant. }\end{array} \) \\
\hline B. & \( \begin{array}{l}\text { A charge particle is } \\
\text { moving in uniform } \\
\text { electric, magnetic } \\
\text { and gravitational } \\
\text { fields. }\end{array} \) & q. & \( \begin{array}{l}\text { Path of the particle may } \\
\text { be straight line. }\end{array} \) \\
\hline C. & \( \begin{array}{l}\text { A charge particle is } \\
\text { moving in uniform } \\
\text { magnetic and } \\
\text { gravitational fields } \\
\text { (where electric field } \\
\text { is zero). }\end{array} \) & r. & \( \begin{array}{l}\text { Path of the particle may } \\
\text { be circular. }\end{array} \) \\
\hline D. & \( \begin{array}{l}\text { A charge particle } \\
\text { is moving in only } \\
\text { uniform electric field. }\end{array} \) & s. & \( \begin{array}{l}\text { Path of the particle may } \\
\text { be helical. }\end{array} \) \\
\hline
\end{tabular}
(1) A-(p,s); B-(p,q,s); C-(p,q,r,s); D-(q)
(2) A-(p,r,s); B-(p,q,r,s); C-(q); D-(p,q,s)
(3) A-(p,q,r,s); B-(p); C-(p,q,s); D-(q)
(4) A-(p,q,s); B-(p,q,r,s); C-(p,q,s); D-(q)
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