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\( \mathrm{ABCD} \) is a trapezium such that \( \mathrm{AB} \) and \( \mathrm{CD} \) are parallel and \( \mathrm{BC} \perp \mathrm{CD} \). If \( \angle \mathrm{ADB}=\theta, \mathrm{BC}=\mathrm{p} \) and
\( \mathrm{P} \) \( \mathrm{CD}=\mathrm{q} \), then \( \mathrm{AB} \) is equal to
(1) \( \frac{\mathrm{p}^{2}+\mathrm{q}^{2} \cos \theta}{\mathrm{p} \cos \theta+\mathrm{q} \sin \theta} \)
(2) \( \frac{\mathrm{p}^{2}+\mathrm{q}^{2}}{\mathrm{p}^{2} \cos \theta+\mathrm{q}^{2} \sin \theta} \)
(3) \( \frac{\left(\mathrm{p}^{2}+\mathrm{q}^{2}\right) \sin \theta}{(\mathrm{p} \cos \theta+\mathrm{q} \sin \theta)^{2}} \)
(4) \( \frac{\left(\mathrm{p}^{2}+\mathrm{q}^{2}\right) \sin \theta}{\mathrm{p} \cos \theta+\mathrm{q} \sin \theta} \)
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