n-Butyl alcohol on dehydration forms \( \beta \) - butylene as P th...
n-Butyl alcohol on dehydration forms \( \beta \) - butylene as
P the chief product. This happens because of the
W rearrangement
(1) \( \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2} \) to
\[
\mathrm{CH}_{3}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}-\mathrm{CH}_{2}-\mathrm{CH}_{3}
\]
(2) \( \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2} \) to
\[
\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}
\]
(3) \( \mathrm{CH}_{3}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}-\mathrm{CH}_{2}-\mathrm{CH}_{3} \) to \( \left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}} \)
(4) \( \left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}} \) to \( \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2} \)
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