On adding \( 100 \mathrm{~mL} \) of \( 10^{-2} \mathrm{M} \mathrm{N...

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On adding \( 100 \mathrm{~mL} \) of \( 10^{-2} \mathrm{M} \mathrm{NaOH} \) solution to \( 100 \mathrm{~mL} \) of \( 0.01 \mathrm{M} \) Triethyl amine solution \( \left(\mathrm{K}_{\mathrm{b}}=6.4 \times 10^{-5}\right) \), change in \( \mathrm{pH} \) of solution with respect to triethylamine solution will be :
(A) \( -0.8 \)
(B) \( +0.8 \)
(C) \( +1.1 \)
(D) \( -1.1 \)
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