pH of a solution obtained by mixing equal volumes of \( 0.1 \mathrm...

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pH of a solution obtained by mixing equal volumes of \( 0.1 \mathrm{M} \) Triethyl amine \( \left(K_{b}=6.4 \times 10^{-5}\right) \& \frac{4}{45} M \) \( \mathrm{NH}_{4} \mathrm{OH}\left(\mathrm{K}_{\mathrm{b}}=1.8 \times 10^{-5}\right) \) will be :
(A) \( 11.3 \)
(B) \( 10.3 \)
(C) \( 12.3 \)
(D) \( 11.45 \)
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