Palindrome Partitioning II | Using Blue Print | DP On Strings | Leetcode 132 | DP Concepts & Qns-28
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This is the 28th Video of our Playlist "DP Concepts & Qns" by codestorywithMIK
This is the tenth video of the "DP On Strings" series in this playlist.
In this video we will try to solve a good DP on strings problem : Palindrome Partitioning II | Using Blue Print | DP On Strings | Leetcode 132 | DP Concepts & Qns-28 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Palindrome Partitioning II | Using Blue Print | DP On Strings | Leetcode 132 | DP Concepts & Qns-28 | codestorywithMIK
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My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/palindr...
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My Graph Concepts Playlist : • Graph Concepts & Qns - 1 : Graph will...
My Segment Tree Concepts Playlist : • Segment Tree | Introduction | Basics ...
My Recursion Concepts Playlist : • Introduction | Recursion Concepts And...
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Approaches Summary :
Approach 1: Recursion + Memoization (TLE)
Time Complexity: O(n^3)
Space Complexity: O(n^2)
Description: This approach uses recursion with memoization to solve the problem of finding the minimum number of cuts needed to partition a string into palindromes. The function recursively checks if a substring is a palindrome, and if not, it tries all possible partitions to minimize the cuts. The memoization table t[i][j] is used to store results of subproblems to avoid recomputation. However, due to its cubic time complexity, it results in a Time Limit Exceeded (TLE) error for larger inputs.
Approach 2: Bottom-Up (Accepted)
Time Complexity: O(n^2)
Space Complexity: O(n^2)
Description: This approach uses dynamic programming in a bottom-up manner to optimize the solution. It first constructs a 2D table P[i][j] where each entry indicates whether a substring is a palindrome. After that, it builds a table t[] to store the minimum cuts required for each prefix of the string. By iterating through possible partitions and checking the precomputed palindrome table, this method efficiently computes the result in quadratic time and space, making it an accepted solution.
✨ Timelines✨
00:00 - Introduction
0:11 - Motivation
1:46 - Problem Explanation
4:37 - Recursion + Memo
7:29 - Tree Diagram Dry Run
14:58 - Story To Code (Recursion + Memo)
20:00 - Coding Recursion + Memo
26:39 - Bottom Up (BluePrint)
28:34 - Dry Run with example
47:42 - Story Points
50:29 - Coding Bottom Up
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