Linked List in Binary Tree | Easy | Dry Run | Leetcode 1367 | codestorywithMIK
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This is the 49th Video of our Playlist "Binary Tree : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a simple Binary Tree Problem : Linked List in Binary Tree | Easy | Dry Run | Leetcode 1367 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Linked List in Binary Tree | Easy | Dry Run | Leetcode 1367 | codestorywithMIK
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Summary :
The approach leverages recursion to check whether a linked list exists as a subpath in a binary tree. It involves two key functions:
check Function: This helper function recursively checks if a path in the binary tree matches the linked list starting from a specific tree node. If a complete match is found (i.e., the linked list is fully traversed), it returns true. If the current tree node is null or the values do not match, it returns false. It checks both the left and right subtrees for a potential match.
isSubPath Function: This is the main function that recursively searches through the binary tree, starting from the root. It calls the check function to see if a valid path starts at the current tree node. If not, it recursively checks the left and right children of the current node.
The algorithm performs a depth-first search (DFS) on the tree and checks all possible paths, making it a backtracking solution that explores all branches where a valid subpath could exist.
✨ Timelines✨
00:00 - Introduction
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