Convert 1D Array Into 2D Array | 2 Approaches | Leetcode 2022 | codestorywithMIK

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Published on September 1, 2024 5:48:04 AM ● Video Link: https://www.youtube.com/watch?v=4jQErv8WK6o

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This is the 53rd Video of our Playlist "Leetcode Easy : Popular Interview Problems" by codestorywithMIK

In this video we will try to solve an easy problem : Convert 1D Array Into 2D Array | 2 Approaches | Leetcode 2022 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
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Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Convert 1D Array Into 2D Array | 2 Approaches | Leetcode 2022 | codestorywithMIK
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Leetcode Link : https://leetcode.com/problems/convert...


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Summary :
Both approaches convert a 1D array (original) into a 2D array (result) with m rows and n columns. However, they differ in how they populate the 2D array.

First Approach (Nested Loops):

This method uses two nested loops: the outer loop iterates over the rows, and the inner loop iterates over the columns.
It keeps track of an index (idx) that is used to access elements in the 1D array and place them in the 2D array sequentially.
Simple and intuitive, especially when thinking about 2D arrays as rows and columns.
Second Approach (Single Loop with Division/Modulus):

Instead of nested loops, this approach uses a single loop that iterates over the entire length of the original array.
It calculates the row index as i / n and the column index as i % n to directly place elements into the 2D array.
This approach is more compact, leveraging division and modulus operations to map 1D indices to 2D indices.
Both methods check if the total number of elements in the original array matches m * n before proceeding. If not, they return an empty 2D array.


✨ Timelines✨
00:00 - Introduction

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