\( S_{r}=\left|\begin{array}{lll}2 r & x & n(n+1) \\ 6 r^{2}-1 & y & n^{2}(2 n+3) \\ 4 r^{3}-2 n...

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\( S_{r}=\left|\begin{array}{lll}2 r & x & n(n+1) \\ 6 r^{2}-1 & y & n^{2}(2 n+3) \\ 4 r^{3}-2 n r & z & n^{3}(n+1)\end{array}\right| \) then \( \sum_{r=1}^{n} S_{r} \) does not depend on
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