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The circuit shown in the figure consists of a battery of \( \operatorname{emf} \varepsilon=10 \mathrm{~V} \); a capacitor of capacitance \( \mathrm{C}=1.0 \mu \mathrm{F} \) and three resistor of values \( \mathrm{R}_{1}=2 \Omega, \mathrm{R}_{2}=2 \Omega \) and \( \mathrm{R}_{3}=1 \Omega \). Initially the capacitor is completely uncharged and the switch \( \mathrm{S} \) is open. The switch \( \mathrm{S} \) is closed at \( \mathrm{t}=0 \).
(A) The current through resistor \( \mathrm{R}_{3} \) at the moment the switch closed is zero.
\( \mathrm{P} \)
(B) The current through resistor \( R_{3} \) a long time after the switch closed is \( 5 \mathrm{~A} \).
(C) The ratio of current through \( \mathrm{R}_{1} \) and \( \mathrm{R}_{2} \) is always constant.
(D) The maximum charge on the capacitor during the operation is \( 5 \mu \mathrm{C} \).
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