The energy of a particle executing simple harmonic motion is given ...
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The energy of a particle executing simple harmonic motion is given by \( \mathrm{E}=\mathrm{Ax}^{2}+\mathrm{Bv}^{2} \), where
\( \mathrm{P} \) \( \mathrm{x} \) is the displacement from mean position \( \mathrm{x}=0 \)
W and \( v \) is the velocity of the particle at \( x \) then choose the INCORRECT statement.
(1) Amplitude of SHM is \( \sqrt{\frac{2 E}{A}} \)
(2) Maximum velocity of the particle during SHM is \( \sqrt{\frac{E}{B}} \)
(3) Time period of motion is \( 2 \pi \sqrt{\frac{B}{A}} \)
(4) Maximum acceleration of particle is \( \frac{1}{\mathrm{~B}} \sqrt{\frac{\mathrm{EA}}{1}} \)
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