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The energy of a particle executing simple harmonic motion is given by \( E=A x+B v^{2} \), where \( x \) is the displacement from mean position \( x=0 \) and \( v \) is the velocity of the particle at \( x \) and \( A \) and \( B \)
\( \mathrm{P} \) are constants. Then, choose the correct statement(s).
(a) Amplitude of SHM is \( \sqrt{\frac{2 E}{A}} \)
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(b) Maximum velocity of the particle during SHM is \( \sqrt{\frac{E}{B}} \)
(c) Time period of motion is \( 2 \pi \sqrt{\frac{B}{A}} \)
(d) Displacement of the particle is proportional to the velocity of the particle
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