The equilibrium constants for the reactions are : \[ \begin{array}{l} \mathrm{H}_{3} \mathrm{PO}...
The equilibrium constants for the reactions are :
\[
\begin{array}{l}
\mathrm{H}_{3} \mathrm{PO}_{4} \stackrel{K_{1}}{\rightleftharpoons} \mathrm{H}^{+}+\mathrm{H}_{2} \mathrm{PO}_{4}^{-} ; \quad K_{1} \\
\mathrm{H}_{2} \mathrm{PO}_{4}^{-} \stackrel{K_{2}}{\rightleftharpoons} \mathrm{H}^{+}+\mathrm{HPO}_{4}^{2-} ; \quad K_{2} \\
\mathrm{HPO}_{4}^{2-} \stackrel{K_{3}}{\rightleftharpoons} \mathrm{H}^{+}+\mathrm{PO}_{4}^{3-} ; \quad K_{3}
\end{array}
\]
The equilibrium constant for, \( \mathrm{H}_{3} \mathrm{PO}_{4} \rightleftharpoons 3 \mathrm{H}^{+}+\mathrm{PO}_{4}^{3-} \) will be :
(A) \( K_{1} / K_{2} K_{3} \)
(B) \( K_{1} \times K_{2} \times K_{3} \)
(C) \( K_{2} / K_{1} K_{3} \)
(D) \( K_{1}+K_{2}+K_{3} \)
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