The expression \( \alpha=\Lambda / \Lambda_{0} \) will not hold good for the electrolyte (A) \( ...
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0The expression \( \alpha=\Lambda / \Lambda_{0} \) will not hold good for the electrolyte
(A) \( \mathrm{HOCN} \)
(B) \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \)
(C) \( \mathrm{H}_{2} \mathrm{SO}_{4} \)
(D) \( \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} \)
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