The peak value of an alternating e.m.f. \( E \) is given by P \( \m...
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The peak value of an alternating e.m.f. \( E \) is given by
P \( \mathrm{E}=\mathrm{E}_{0} \cos \omega \mathrm{t} \) is 10 volts and its frequency is \( 50 \mathrm{~Hz} \).
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At time \( t=\frac{1}{600} \sec \), the instantaneous e.m.f. is
(1) \( 10 \mathrm{~V} \)
(2) \( 5 \sqrt{3} \mathrm{~V} \)
(3) \( 5 V \)
(4) \( 1 \mathrm{~V} \)
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