The solubility of \( \mathrm{AgI} \) in \( \mathrm{NaI} \) solution is less than that in pure wa...
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The solubility of \( \mathrm{AgI} \) in \( \mathrm{NaI} \) solution is less than that in pure water because :
(a) the temperature of the solution decreases
(b) solubility product to \( \mathrm{AgI} \) is less than that of \( \mathrm{NaI} \)
(c) of common ion effect
(d) AgI forms complex with \( \mathrm{NaI} \)
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