The speed of a projectile at its highest point is \( v_{1} \) and at the point half the maximum ...
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0The speed of a projectile at its highest point is \( v_{1} \) and at the point half the maximum height is \( v_{2} \). If \( \frac{v_{1}}{v_{2}}=\sqrt{\frac{2}{5}} \), then find the angle of projection.
(1) \( 45^{\circ} \)
(2) \( 30^{\circ} \)
(3) \( 37^{\circ} \)
(4) \( 60^{\circ} \)
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