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The strength of \( \mathrm{H}_{2} \mathrm{O}_{2} \) is expressed in several ways like molarity, normality, \( \%(w / \mathrm{V}) \), volume strength, etc. The strength of "10 V" means 1 volume of
\( \mathrm{P} \) \( \mathrm{H}_{2} \mathrm{O}_{2} \) on decomposition gives 10 volumes of oxygen at \( 1 \mathrm{~atm} \) and \( 273 \mathrm{~K} \) or 1

W litre of \( \mathrm{H}_{2} \mathrm{O}_{2} \) gives 10 litre of \( \mathrm{O}_{2} \) at \( 1 \mathrm{~atm} \) and \( 273 \mathrm{~K} \) The decomposition of \( \mathrm{H}_{2} \mathrm{O}_{2} \) is shown as under :
\[
\mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\frac{1}{2} \mathrm{O}_{2}(g)
\]
\( \mathrm{H}_{2} \mathrm{O}_{2} \) can acts as oxidising as well as reducing agent. As oxidizing agent \( \mathrm{H}_{2} \mathrm{O}_{2} \) is converted into \( \mathrm{H}_{2} \mathrm{O} \) and as reducing agent \( \mathrm{H}_{2} \mathrm{O}_{2} \) is converted into \( \mathrm{O}_{2} \). For both cases its \( n \)-factor is 2 .
\( \therefore \) Normality of \( \mathrm{H}_{2} \mathrm{O}_{2} \) solution \( =2 \times \) Molarity of \( \mathrm{H}_{2} \mathrm{O}_{2} \) solution \( 20 \mathrm{~mL} \) of \( \mathrm{H}_{2} \mathrm{O}_{2} \) solution is reacted with \( 80 \mathrm{~mL} \) of \( 0.05 \mathrm{M} \mathrm{KMnO}_{4} \) in acidic medium then what is the volume strength of \( \mathrm{H}_{2} \mathrm{O}_{2} \) ?
(a) 2.8
(b) 5.6
(c) 11.2
(d) None of these
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