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The work-function of caesium metal is \( 2.14 \mathrm{eV} \).
When light of frequency \( 6 \times 10^{14} \mathrm{~Hz} \) is incident on the metal surface, photoemission of electrons occurs.
What is the
- (i) stopping potential and
(ii) maximum speed of the emitted photoelectrons?
(a) \( V_{0}=0.35 \mathrm{~V}, V_{\max }=350.7 \mathrm{kms}^{-1} \)
(b) \( V_{0}=.2 \mathrm{~V}, V_{\max }=250 \mathrm{kms}^{-1} \)
(c) \( V_{0}=1.2 \mathrm{~V}, V_{\max }=250 \mathrm{kms}^{-1} \)
(d) None of the above
\( \mathrm{P} \)
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