Three boys and two girls stand in a queue. The probability, that the number of boys ahead of eve...

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Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at least one more than the number of girls ahead of her, is -
\( P \)
(A) \( \frac{1}{2} \)
(B) \( \frac{1}{3} \)
(C) \( \frac{2}{3} \)
(D) \( \frac{3}{4} \)
W.
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