Under the action of force, \( 1 \mathrm{~kg} \) body moves such that its position \( x \) as a f....

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Under the action of force, \( 1 \mathrm{~kg} \) body moves such that its position \( x \) as a function of time \( t \) is given by
\( \mathrm{P} \)
\( x=\frac{t^{3}}{3}, x \) is in meter. Calculate the work done (in joules) by the force in first 2 seconds.


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