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While performing a thermodynamics experiment, a student made the following observation.\[\begin{aligned}& \mathrm{HCl}+\mathrm{NaOH} \rightarrow \mathrm{NaCl}+\mathrm{H}_2 \mathrm{O} \Delta \mathrm{H}=-57.3 \mathrm{~kJ} \mathrm{~mol}^{-1} \\& \mathrm{CH}_3 \mathrm{COOH}+\mathrm{NaOH} \rightarrow \mathrm{CH}_3 \mathrm{COONa}+\mathrm{H}_2 \mathrm{O} \Delta \mathrm{H}=-55.3 \mathrm{~kJ} \mathrm{~mol}^{-1}\end{aligned}\]
The enthalpy of ionization of \(\mathrm{CH}_3 \mathrm{COOH}\) as calculated by the student is \(\mathrm{kJ} \mathrm{mol}^{-1}\). (Nearest integer) 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live