A can hit a target 4 times in 5 shots, B can hit it three times in 4 shots and \( \mathrm{C} \) ...

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A can hit a target 4 times in 5 shots, B can hit it three times in 4 shots and \( \mathrm{C} \) can hit it twice in 3 shots. They fire at target if exactly two of them hit the target. Then the chance that it is \( \mathrm{C} \) who has missed is
(A) \( \frac{6}{13} \)
(B) \( \frac{1}{5} \)
(C) \( \frac{4}{5} \)
(D) \( \frac{4}{15} \)
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