A drop of water volume 0.05 \(\displaystyle cm^{3}\) is pressed between two glass-plates as a co...
Channel:
Subscribers:
447,000
Published on ● Video Link: https://www.youtube.com/watch?v=Js5pah7wWI4
A drop of water volume 0.05 \(\displaystyle cm^{3}\) is pressed between two glass-plates as a consequence of which it spreads and occupies an area of 40 \(\displaystyle cm^{3}\). If the surface tension of water is 70 dyne/cm, find the normal force required to separate out the two glass plates in Newton
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live