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A mass falls from a height \( h \) and its time of fall \( t \) is recorded in terms of time period \( T \) of a simple pendulum. On the surface of earth, it is found that \( t=2 T \). The entire set up is taken on the surface of another planet whose mass is half of earth and radius the same. Same experiment is repeated and corresponding times are noted as \( t^{\prime} \) and \( T^{\prime} \).
(a) \( t^{\prime}=\sqrt{2} T^{\prime} \) (b) \( t^{\prime}2 T^{\prime} \)
(c) \( t^{\prime}2 T^{\prime} \)
(d) \( t^{\prime}=2 T^{\prime} \)
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