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A steady current 'l' flows in a small square loop of wire of side L in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let \( \vec{\mu}_{1} \) and \( \vec{\mu}_{2} \) respectively denote the magnetic moments of the current loop before and after folding. Then :
(A) \( \vec{\mu}_{2}=0 \)
(B) \( \vec{\mu}_{1} \) and \( \vec{\mu}_{2} \) are in the same direction
(C) \( \frac{\left|\vec{\mu}_{1}\right|}{\left|\vec{\mu}_{2}\right|}=\sqrt{2} \)
(D) \( \frac{\left|\vec{\mu}_{1}\right|}{\left|\vec{\mu}_{2}\right|}=\frac{1}{\sqrt{2}} \)
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