Array Pair Sum Divisibility Problem | Brute Force | Optimal | GfG POTD
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This is the 10th Video of our Playlist "Hash Map/Set".
In this video we will try to solve a good interview problem - Array Pair Sum Divisibility Problem
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Array Pair Sum Divisibility Problem
Company Tags : Amazon, Microsoft, Goldman Sachs, Directi
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/HashSet/Array%20Pair%20Sum%20Divisibility%20Problem.cpp
Leetcode Link : https://www.geeksforgeeks.org/problems/array-pair-sum-divisibility-problem3257/1
My DP Concepts Playlist : https://youtu.be/7eLMOE1jnls
My Graph Concepts Playlist : https://youtu.be/5JGiZnr6B5w
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Interview_DS_Algo
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Approach-1 Summary : The method uses a greedy approach to find pairs, iterating through the vector and marking elements as used to avoid repetition. It checks for pairs by comparing the sum of elements at different positions and verifies if the sum is divisible by k. If a valid pair is found, both elements are marked as used. If no pair is found for a particular element, the method returns false, indicating that no valid pairing exists. If all elements can be paired successfully, the method returns true.
Approach-2 Summary : The approach uses an unordered set (st) to keep track of remainders when dividing elements by k. It iterates through the vector, and for each element, it calculates its remainder and the remainder of the complement needed to make the sum divisible by k. If the complement remainder is found in the set or the current element has a remainder of 0 and 0 is present in the set, it means a valid pair is found, and both elements are removed from the set. Otherwise, the remainder is added to the set. The method returns true if, after processing all elements, the set is empty, indicating that all elements could be successfully paired to satisfy the divisibility condition. Additionally, the method checks if the size of the vector is odd, returning false immediately if so, as an even number of elements is required for pairing.
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✨ Timelines✨
00:00 - Introduction
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