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Calculate the heat of formation of \( \mathrm{PCl}_{5}(\mathrm{~s}) \) from the
P following data:

W
\[
\begin{array}{l}
2 \mathrm{P}(\mathrm{s})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{PCl}_{3}(\mathrm{l}) \quad \Delta \mathrm{H}=-151.8 \mathrm{kcal} \\
\mathrm{PCl}_{3}(\mathrm{l})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow \mathrm{PCl}_{5}(\mathrm{~s}) \Delta \mathrm{H}=-32.8 \mathrm{kcal}
\end{array}
\]
(1) \( -108.7 \mathrm{kcal} \)
(2) \( 108.7 \mathrm{kcal} \)
(3) \( -184.6 \mathrm{kcal} \)
(4) \( 184.6 \mathrm{kcal} \)
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