Consider the equation \( x^{3}-a x^{2}+b x-c=0 \), where \( a \),
\( b, c, \in Q ;(a \neq 1) \)..... VIDEO
Consider the equation \( x^{3}-a x^{2}+b x-c=0 \), where \( a \),
\( \mathrm{P} \)
\( b, c, \in Q ;(a \neq 1) \). If is given that \( x_{1}, x_{2} \) and \( x_{1} x_{2} \) are
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the real roots of the equation. If \( b+c=2(a+1) \), then \( x_{1} x_{2}\left(\frac{a+1}{b+c}\right) \) is equal to.
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