Duration: 7:00

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Constructa triangle XYZ in which \( \angle Y=30^{\circ}, \angle Z=90^{\circ} \) and \( X Y+Y Z+Z X=11 \mathrm{~cm} \).
Aus: Steps of Constrution:
(i) traw a line segment \( A B=11 \mathrm{~cm} \).
(ii) \( A+A \), draw \( \angle B A P=30^{\circ} \) and at \( B \), draw \( \angle A B R=90^{\circ} \)
(iii) Draw the bisector of \( \angle B A P \) and \( \angle A B R \), which intersect each other at \( Y \).
(iv) Join Ayand BY
(v) Draw the perpendicular nisectors LM and ST of \( A Y \) and \( B Y \) respectively. LM and \( \delta^{\circ} T \) intersect \( A B \) at \( X \) and \( Z \) respectively.
Iid eyi) Join \( x y \) and \( y z \)
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