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If \( y=e^{-x}(A \cos x+B \sin x) \), then \( y \) is a solution of
(A) \( \frac{d^{2} y}{d x^{2}}+2 \frac{d y}{d x}=0 \)
(B) \( \frac{d^{2} y}{d x^{2}}-2 \frac{d y}{d x}+2 y=0 \)
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(C) \( \frac{d^{2} y}{d x^{2}}+2 \frac{d y}{d x}+2 y=0 \)
(D) \( \frac{d^{2} y}{d x^{2}}+2 y=0 \)
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