XOR Queries of a Subarray | Simple Explanation | Leetcode 1310 | codestorywithMIK
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In this video we will try to solve an easy problem : XOR Queries of a Subarray | Simple Exlpanation | Leetcode 1310 | codestorywithMIK
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Problem Name : XOR Queries of a Subarray | Simple Explanation | Leetcode 1310 | codestorywithMIK
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Summary :
The problem is solved using cumulative XOR (prefix XOR) to efficiently handle multiple range XOR queries. The approach involves two main steps:
Precompute Cumulative XOR:
First, we create an array cumXor where each element cumXor[i] stores the XOR of all elements in the input array arr from the beginning up to index i. This allows us to compute the XOR of any subarray in constant time.
The cumulative XOR is computed in a single pass over the array (O(n)).
Answer Queries Efficiently:
For each query, which provides a range [L, R], the XOR of the subarray from L to R is computed as cumXor[R] ^ cumXor[L-1]. If L is 0, the XOR result is simply cumXor[R].
This allows each query to be processed in constant time (O(1)), making the overall time complexity O(n + q), where n is the size of the array and q is the number of queries.
This approach is efficient because it reduces the time complexity from O(n*q) (brute force) to O(n + q) by using precomputed values.
✨ Timelines✨
00:00 - Introduction
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