Diameter and mass of a planet is double that earth. Then time period of a pendulum at surface of...

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Diameter and mass of a planet is double that earth. Then time period of a pendulum at surface of planet is how much times of time period at earth surface :-
(1) \( \frac{1}{\sqrt{2}} \) times
(2) \( \sqrt{2} \) times
(3) Equal
(4) None of these
\( \mathrm{P} \)
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