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Five identical charges are kept at five vertices of a regular hexagon. Match the following two columns at centre of the hexagon. If in the given situation electric field at centre is \( E \). Then,
\( \mathrm{P} \)
W
Column I
Column It
(a) If charge at \( B \) is removed. then electric field will become
(p) \( 2 E \)
\( \begin{array}{ll}\text { (b) If charge at } C \text { is removed, then electric field will become } & \text { (q) } E\end{array} \)
(c) If chaige at \( D \) is removed then electric field will become (r) zero
(d) If charges at \( B \) and \( C \) both are removed, then electric (s) \( \sqrt{3} E \) field will become
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