House Robber IV | Brute Force | Optimal | Leetcode 2560 | codestorywithMIK

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Published on March 15, 2025 5:07:35 AM ● Video Link: https://www.youtube.com/watch?v=YrRvP9720vY

Game:

Brute Force (2003)

Duration: 0:00

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Binary Search (Popular Interview Problems) Playlist -    • Find First & Last Position Of Element...  

Hi Everyone, this is the 38th video of our Playlist "Binary Search: Popular Interview Problems".
Now we will be solving a very a good problem based on Binary Search on Answer -
House Robber IV | Brute Force | Optimal | Leetcode 2560 | codestorywithMIK

We will start from Brute Force to see the importance of it and will deduce the optimal approach by looking carefully that this problem is also falling in the category of
"Minimize the Maximum" or "Maximize the Minimum"

Problem Name : House Robber IV | Brute Force | Optimal | Leetcode 2560 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Binary Search/House Robber IV.cpp
Leetcode Link : https://leetcode.com/problems/house-robber-iv


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Video Summary :
Approach 1 (Brute Force - Recursion + Memoization):
This approach explores all possible ways to rob exactly k houses while skipping adjacent ones. It recursively decides whether to take or skip a house, using memoization to avoid redundant calculations.

Approach 2 (Binary Search on Answer - Minimize the Maximum Robbed Amount):
Instead of directly selecting houses, this approach uses binary search on the minimum capability required to rob k houses. It checks if it's possible to rob at most k houses with a given capability and adjusts the search range accordingly.


✨ Timelines✨
00:00 - Introduction
0:14 - Motivation
0:33 - Problem Explanation
4:23 - Brute Force
5:57 - Tree Diagram
14:26 - Coding Brute Force
17:54 - Careful Observation, Why Binary Search on Answer ?
20:09 - Dry Run
28:36 - One Important Qn
34:31 - Coding Optimal Approach

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