If \( A B C D E F \) is regular hexgon, then \( \mathrm{AD}+\mathrm{EB}+\mathrm{FC} \) is equal ...

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If \( A B C D E F \) is regular hexgon, then \( \mathrm{AD}+\mathrm{EB}+\mathrm{FC} \) is equal to
(a) 0
(b) \( 2 A B \)
(c) \( 3 A B \)
(d) \( 4 A B \)
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