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If the length of the day is \( T \), the height of that \( T V \) satellite above the earths surface which always appears stationary from earth, will be :
(1) \( \mathrm{h}=\left[\frac{4 \pi^{2} G M}{\mathrm{~T}^{2}}\right]^{1 / 3} \)
(2) \( \mathrm{h}=\left[\frac{4 \pi^{2} G M}{\mathrm{~T}^{2}}\right]^{1 / 2}-\mathrm{R} \)
(3) \( \mathrm{h}=\left[\frac{\mathrm{GMT}^{2}}{4 \pi^{2}}\right]^{1 / 3}-\mathrm{R} \)
(4) \( h=\left\lceil\frac{\mathrm{GMT}^{2}}{4 \pi^{2}}\right]^{1 / 3}+\mathrm{R} \)
\( \mathrm{P} \)
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