In a photo-emissive cell, with exciting wavelength \( \lambda \), the maximum kinetic energy of ... VIDEO
In a photo-emissive cell, with exciting wavelength \( \lambda \), the maximum kinetic energy of electron is \( \mathrm{K} \). If the exciting wavelength is changed to \( \frac{3 \lambda}{4} \) the kinetic energy of the fastest emitted electron will be:https://bit.ly/YTAI_PWAP https://www.pw.live
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