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Let \( A=\left[\begin{array}{lll}2 & 2 & 1 \\ 2 & 5 & 2 \\ 1 & 2 & 2\end{array}\right] \) and \( B=\left[\begin{array}{ccc}-x & -y & z \\ 0 & y & 2 z \\ x & -y & z\end{array}\right] \) where \( x, y, z \in R \). If \( B^{\mathrm{T}} A B=\left[\begin{array}{ccc}8 & 0 & 0 \\ 0 & 27 & 0 \\ 0 & 0 & 42\end{array}\right] \) then the number of ordered triplet \( (\mathrm{x}, \mathrm{y}, \mathrm{z}) \) is-
(A) 2
(B) 6
(C) 8
(D) 9
\( \mathrm{P} \)
W
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