Let \( \mathrm{U}_{1} \) and \( \mathrm{U}_{2} \) be two urns such ...
Let \( \mathrm{U}_{1} \) and \( \mathrm{U}_{2} \) be two urns such that \( \mathrm{U}_{1} \) contains 3 white and 2 red balls, and \( \mathrm{U}_{2} \) contains only 1 white ball. A fair coin is tossed. If head appears then 1 ball is drawn at random from \( U_{1} \) and
\( \mathrm{P} \) put into \( \mathrm{U}_{2} \). However, if tail appears then 2 balls are drawn at random from \( \mathrm{U}_{1} \) and put into
W \( \mathrm{U}_{2} \). Now 1 ball is drawn at random from \( \mathrm{U}_{2} \).
Given that the drawn ball from \( \mathrm{U}_{2} \) is white, the probability that head appeared on the coin is -
(A) \( \frac{17}{23} \)
(B) \( \frac{11}{23} \)
(C) \( \frac{15}{23} \)
(D) \( \frac{12}{23} \)
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