Let the area of the triangle with vertices \( A(1, \alpha), B(\alpha, 0) \) and \( C(0, \alpha) ... VIDEO
Let the area of the triangle with vertices \( A(1, \alpha), B(\alpha, 0) \) and \( C(0, \alpha) \) be 4 sq. units. If the points \( (\alpha-\alpha),(-\alpha, \alpha) \) and \( \left(\alpha^{2}, \beta\right) \) are collinear, then \( \beta \) is equal to
(a) 64
(b) -8
(c) -64
(d) 512
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