Let \( y=f(x) \) and \( x=\frac{1}{z} \). If \( \frac{d^{2} y}{d x^{2}}=\lambda z^{3} \frac{d y}...
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Let \( y=f(x) \) and \( x=\frac{1}{z} \). If \( \frac{d^{2} y}{d x^{2}}=\lambda z^{3} \frac{d y}{d z}+z^{4} \frac{d^{2} y}{d z^{2}} \), then
\( \mathrm{P} \) the value of \( \lambda \) is
W
(1) 1
(2) 2
(3) \( \frac{1}{2} \)
(4) \( \frac{1}{4} \)
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