Longest Unequal Adjacent Groups Subsequence II | Why Greedy Fails | Leetcode 2901 | codestorywithMIK
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Hi Everyone, this is the 112th video of our Playlist "Dynamic Programming : Popular Interview Problems".
Now we will be solving a very good DP Problem based on LIS Variant - Longest Unequal Adjacent Groups Subsequence II | Why Greedy Fails | Leetcode 2901 | codestorywithMIK
I will explain it in full detail so that it becomes easy to understand. Each line will be explained and you will know the WHY behind everything.
We will also understand why Greedy fails. We will deep dive so that the thought process will be cleared.
Problem Name : Longest Unequal Adjacent Groups Subsequence II | Why Greedy Fails | Leetcode 2901 | codestorywithMIK
Company Tags : will update later
Code Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/DP/LIS
Leetcode Link - https://leetcode.com/problems/longest-unequal-adjacent-groups-subsequence-ii/description/
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Video Summary :
This problem is solved using a variant of Longest Increasing Subsequence (LIS). We treat each word as a potential end of a valid subsequence and use DP (dp[i]) to store the length of the longest valid chain ending at index i. For each pair of words (j, i), we check if the groups are unequal, word lengths match, and the Hamming distance is exactly 1 — if so, we try extending the subsequence. A parent[] array helps reconstruct the actual sequence at the end.
✨ Timelines✨
00:00 - Introduction
0:15 - Motivation
0:30 - Problem Explanation
4:01 - Why does Greedy fail here ?
7:19 - How is it an LIS Pattern Problem ?
9:52 - Applying LIS Pattern
14:10 - Coding it up
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