Total Characters in String After Transformations I | Made Easy | Leetcode 3335 | codestorywithMIK
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Hi Everyone, this is the 19th video of our Playlist "Hash Map/Set : Popular Interview Problems".
Now we will be solving a good Hashmap problem - Total Characters in String After Transformations I | Brute Force | Optimal | Leetcode 3335 | codestorywithMIK
I will explain in such a way that it will become super easy. We will start from brute force and them improve the solution. Just like Story To Code
Problem Name : Total Characters in String After Transformations I | Brute Force | Optimal | Leetcode 3335 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/HashMap/Total Characters in String After Transformations I.cpp
Leetcode Link : https://leetcode.com/problems/total-characters-in-string-after-transformations-i
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Video Summary :
The intuition behind the solution is to simulate t rounds of character transformations based on defined rules: each character shifts forward in the alphabet, and 'z' splits into 'a' and 'b'. A frequency array tracks how many of each character exist after each round. This avoids working with actual strings, making the approach efficient. The final result is the sum of all character frequencies after t transformations, computed modulo 109+7.
✨ Timelines✨
00:00 - Introduction
0:15 - Motivation
0:29 - Problem Explanation
2:13 - Brute Force
3:37 - Thought Process
8:29 - Story To Code
15:02 - Coding it up
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