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Match the List-I with List-II.
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ List-I } & \multicolumn{2}{c|}{ List-II } \\
\hline (a) & \( \begin{array}{l}\text { Metacentric } \\
\text { chromosome }\end{array} \) & (i) & \( \begin{array}{l}\text { Centromere situated close to the } \\
\text { end forming one extremely short } \\
\text { and one very long arms }\end{array} \) \\
\hline (b) & \( \begin{array}{l}\text { Acrocentric } \\
\text { chromosome }\end{array} \) & (ii) & \( \begin{array}{l}\text { Centromere at the terminal end }\end{array} \) \\
\hline (c) & \( \begin{array}{l}\text { Submetacen- } \\
\text { tric }\end{array} \) & (iii) & \( \begin{array}{l}\text { Centromere in the middle forming } \\
\text { two equal arms of chromosomes }\end{array} \) \\
\hline (d) & \( \begin{array}{l}\text { Telocentric } \\
\text { chromosome }\end{array} \) & (iv) & \( \begin{array}{l}\text { Centromere slightly away from } \\
\text { the middle forming one shorter } \\
\text { arm and one longer arm }\end{array} \) \\
\hline
\end{tabular}
Choose the correct answer from the options given below :
(1) (a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
(2) (a)-(iii); (b)-(i); (c)-(iv); (d)-(ii)
(3) (a)-(i); (b)-(iii); (c)-(ii); (d)-(iv)
(4) (a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)
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